In the Solvay process,can we obtain sodium carbonate directly by treating the solution containing $(NH_4)_2CO_3$ with sodium chloride? Explain.

(N/A) The reaction between $(NH_4)_2CO_3$ and $NaCl$ would theoretically produce $Na_2CO_3$ and $NH_4Cl$.
However,both $Na_2CO_3$ and $NH_4Cl$ are highly soluble in water.
Because the products remain in the ionic form in the solution,the equilibrium does not shift in the forward direction to precipitate $Na_2CO_3$.
Therefore,$Na_2CO_3$ cannot be prepared directly by this method.