(A) Contribution of $W$ atoms at the corners $= 8 \times \frac{1}{8} = 1$. Contribution of $O$ atoms at the edges $= 12 \times \frac{1}{4} = 3$. Contr

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(A) Contribution of $W$ atoms at the corners $= 8 \times \frac{1}{8} = 1$. Contribution of $O$ atoms at the edges $= 12 \times \frac{1}{4} = 3$. Contribution of $Na$ atoms at the body center $= 1 \times 1 = 1$. Thus, the ratio of atoms $Na : W : O$ is $1 : 1 : 3$. Therefore, the formula of the compound is $NaWO_3$.

Class 12 Chemistry Solid State Crystal structure and Coordination number

Easy

In the structure of a solid, $W$ atoms are located at the cube corners of the unit cell, $O$ atoms are located at the cube edges, and $Na$ atoms are at the cube centers. The formula of the compound is:

TS EAMCET 2023 All TS EAMCET

A
$NaWO_3$
B
$NaWO$
C
$Na_2W_2O_2$
D
$Na_2WO_3$

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Crystal structure and Coordination number

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In the structure of a solid, $W$ atoms are located at the cube corners of the unit cell, $O$ atoms are located at the cube edges, and $Na$ atoms are at the cube centers. The formula of the compound is:

Similar Questions

$CsBr$ has a $bcc$ structure. If the edge length is $4.3 \ \overset{\circ}{A}$,what is the minimum distance between $Cs^+$ and $Br^-$ ions in $\overset{\circ}{A}$?

The radius of the calcium ion is $94 \text{ pm}$ and the radius of the oxide ion is $146 \text{ pm}$. What is the possible crystal structure of calcium oxide?

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