(A) Using the Law of Sines: $\frac{\sin A}{a} = \frac{\sin B}{b}$.Given $a=7, b=6, A=120^{\circ}$.$\sin B = \frac{b \sin A}{a} = \frac{6 \sin 120^{\ci

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(A) Using the Law of Sines: $\frac{\sin A}{a} = \frac{\sin B}{b}$.Given $a=7, b=6, A=120^{\circ}$.$\sin B = \frac{b \sin A}{a} = \frac{6 \sin 120^{\circ}}{7}$.Since $\sin 120^{\circ} = \frac{\sqrt{3}}{2} \approx 0.866$.$\sin B = \frac{6 \times 0.866}{7} = \frac{5.196}{7} \approx 0.7423$.$B = \arcsin(0.7423) \approx 47.9^{\circ}$.

Class 11 Mathematics Trigonometrical Equations Relation between sides and angles, Solutions of triangles

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In the triangle $ABC$,if $a=7, b=6$ and $A=120^{\circ}$,then the approximate value of $B$ is (in $^{\circ}$)

AP EAMCET 2022 All AP EAMCET

A
$47.9$
B
$44.9$
C
$59.9$
D
$61.9$

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In the triangle $ABC$,if $a=7, b=6$ and $A=120^{\circ}$,then the approximate value of $B$ is (in $^{\circ}$)

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