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(D) The radioactive decay process from uranium to lead involves the emission of $\alpha$-particles and $\beta$-particles.An $\alpha$-particle is a hel

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$8$

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(D) The radioactive decay process from uranium to lead involves the emission of $\alpha$-particles and $\beta$-particles.An $\alpha$-particle is a helium nucleus $(_{2}He^{4})$,which reduces the mass number $(A)$ by $4$ and the atomic number $(Z)$ by $2$.$A$ $\beta$-particle emission does not change the mass number.Let $n_{\alpha}$ be the number of $\alpha$-particles emitted.The change in mass number is given by: $A_{initial} - A_{final} = 4 	imes n_{\alpha}$.Substituting the given values: $238 - 206 = 4 	imes n_{\alpha}$.$32 = 4 	imes n_{\alpha}$.$n_{\alpha} = \frac{32}{4} = 8$.Therefore,$8$ $\alpha$-particles are emitted.

In the uranium radioactive series,the initial nucleus is $_{92}U^{238}$ and the final nucleus is $_{82}Pb^{206}$. When the uranium nucleus decays to lead,the number of $\alpha$-particles emitted will be

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