(D) The resultant intensity $I$ of two interfering waves with amplitudes $a_1$ and $a_2$ and phase difference $\phi$ is given by the formula:$I = a_1^

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$I = A + B \cos \phi$,where $A$ and $B$ depend upon the amplitudes of the two waves.

(D) The resultant intensity $I$ of two interfering waves with amplitudes $a_1$ and $a_2$ and phase difference $\phi$ is given by the formula:$I = a_1^2 + a_2^2 + 2a_1 a_2 \cos \phi$By substituting $A = a_1^2 + a_2^2$ and $B = 2a_1 a_2$,the expression simplifies to:$I = A + B \cos \phi$Thus,option $D$ is correct.

Class 12 Physics Wave Optics Young's Double Slit Experiment (YDSE)

Easy

In the Young's double slit experiment,if the phase difference between the two waves interfering at a point is $\phi$,the intensity at that point can be expressed by the expression:

A
$I = \sqrt{A^2 + B^2 \cos^2 \phi}$
B
$I = \frac{A}{B} \cos \phi$
C
$I = A + B \cos \frac{\phi}{2}$
D
$I = A + B \cos \phi$,where $A$ and $B$ depend upon the amplitudes of the two waves.

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Wave Optics

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Young's Double Slit Experiment (YDSE)

Two sources of light of wavelengths $2500 \,\mathring{A}$ and $3500 \,\mathring{A}$ are used in Young's double slit experiment simultaneously. Which orders of fringes of the two wavelength patterns coincide?

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In the ideal double-slit experiment,when a glass plate (refractive index $\mu = 1.5$) of thickness $t$ is introduced in the path of one of the interfering beams (wavelength $\lambda$),the intensity at the position where the central maximum occurred previously remains unchanged. The minimum thickness of the glass plate is:

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In an interference pattern,the $(n + 4)^{th}$ blue bright fringe and $n^{th}$ red bright fringe are formed at the same spot. If red and blue light have wavelengths of $7800\,\mathring{A}$ and $5200\,\mathring{A}$ respectively,then the value of $n$ is:

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Two parallel slits $0.6 \, mm$ apart are illuminated by a light source of wavelength $6000 \, \mathring{A}$. The distance between two consecutive dark fringes on a screen $1 \, m$ away from the slits is ........ $mm$.

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In Young's double-slit experiment,the angular width of the fringes formed on the screen is $\pi / 200$. If light of wavelength $4800 \, \mathring{A}$ is used,find the distance between the slits.

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In the Young's double slit experiment,if the phase difference between the two waves interfering at a point is $\phi$,the intensity at that point can be expressed by the expression:

Similar Questions

Two sources of light of wavelengths $2500 \,\mathring{A}$ and $3500 \,\mathring{A}$ are used in Young's double slit experiment simultaneously. Which orders of fringes of the two wavelength patterns coincide?

In an interference pattern,the $(n + 4)^{th}$ blue bright fringe and $n^{th}$ red bright fringe are formed at the same spot. If red and blue light have wavelengths of $7800\,\mathring{A}$ and $5200\,\mathring{A}$ respectively,then the value of $n$ is:

Two parallel slits $0.6 \, mm$ apart are illuminated by a light source of wavelength $6000 \, \mathring{A}$. The distance between two consecutive dark fringes on a screen $1 \, m$ away from the slits is ........ $mm$.

In Young's double-slit experiment,the angular width of the fringes formed on the screen is $\pi / 200$. If light of wavelength $4800 \, \mathring{A}$ is used,find the distance between the slits.

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