In thermodynamics,for an isochoric process,wh | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) An isochoric process is defined as a process where the volume of the system remains constant $(dV = 0)$.Since work done $dW = P dV$,if $dV = 0$,th

Vedclass · Accepted Answer

Energy exchanged is used to do work and also to change internal energy

Vedclass · Answer

(A) An isochoric process is defined as a process where the volume of the system remains constant $(dV = 0)$.Since work done $dW = P dV$,if $dV = 0$,then $dW = 0$. Thus,no work is done in the process.According to the first law of thermodynamics,$dQ = dU + dW$. Since $dW = 0$,the heat exchanged $(dQ)$ is entirely used to change the internal energy $(dU)$ of the system.Therefore,statement $(A)$ is incorrect because energy exchanged is not used to do work.

In thermodynamics,for an isochoric process,which one of the following statements is $INCORRECT$?

Similar Questions

When $1 \, mol$ of nitrogen gas is heated at constant pressure at room temperature,it is supplied with $1163.4 \, J$ of energy. The increase in temperature is ....... $K$ $(R = 8.31 \, J \, mol^{-1} \, K^{-1})$.

The ratio of work done by an ideal monoatomic gas to the heat supplied to it in an isobaric process is

$A$ sample of an ideal gas $(\gamma = 5/3)$ is heated at constant pressure. If $100 \ J$ of heat is supplied to the gas,the work done by the gas is: (in $J$)

The work done by a gas is maximum when it expands from a volume $V_1$ to $V_2$. This expansion is:

The volume $(V)$ of a monatomic gas varies with its temperature $(T)$,as shown in the graph. The ratio of work done by the gas to the heat absorbed by it,when it undergoes a change from state $A$ to state $B$,is

Vedclass Test Series

Exam Paper Generator

Online Exam Module