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(B) For equation $I$: $6x^2 + 19x + 15 = 0$$6x^2 + 9x + 10x + 15 = 0$$3x(2x + 3) + 5(2x + 3) = 0$$(3x + 5)(2x + 3) = 0$$x = -5/3 \approx -1.67$ or $x

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If $x \geq y$

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(B) For equation $I$: $6x^2 + 19x + 15 = 0$$6x^2 + 9x + 10x + 15 = 0$$3x(2x + 3) + 5(2x + 3) = 0$$(3x + 5)(2x + 3) = 0$$x = -5/3 \approx -1.67$ or $x = -3/2 = -1.5$For equation $II$: $3y^2 + 11y + 10 = 0$$3y^2 + 6y + 5y + 10 = 0$$3y(y + 2) + 5(y + 2) = 0$$(3y + 5)(y + 2) = 0$$y = -5/3 \approx -1.67$ or $y = -2$Comparing the values:If $x = -1.5$ and $y = -1.67$,then $x > y$.If $x = -1.5$ and $y = -2$,then $x > y$.If $x = -1.67$ and $y = -1.67$,then $x = y$.If $x = -1.67$ and $y = -2$,then $x > y$.In all cases,$x \geq y$.

In these questions,two equations numbered $I$ and $II$ are given. You have to solve both the equations and mark the appropriate option.
$I$. $6x^2 + 19x + 15 = 0$
$II$. $3y^2 + 11y + 10 = 0$

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In these questions,two equations numbered $I$ and $II$ are given. You have to solve both the equations and mark the appropriate option.$I$. $6x^2 + 19x + 15 = 0$$II$. $3y^2 + 11y + 10 = 0$