In the reaction $CH_3CHO + HCN \to CH_3CH(OH)CN \xrightarrow{H_3O^+} CH_3CH(OH)COOH$,an asymmetric center is generated. The acid obtained would be:

  • A
    $20\% \ D + 80\% \ L$ isomer
  • B
    $D$ isomer
  • C
    $L$ isomer
  • D
    $50\% \ D + 50\% \ L$ isomer

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