In a transistor,the forward bias is always kept smaller than the reverse bias. The correct reason is:

For a common base configuration of a $PNP$ transistor,$\frac{I_C}{I_E} = 0.96$. Then,the maximum current gain in common emitter configuration will be:

$A$ transistor is used in common-emitter mode in an amplifier circuit. When a signal of $10 \, mV$ is added to the base-emitter voltage, the base current changes by $10 \, \mu A$ and the collector current changes by $1.5 \, mA$. The load resistance is $5 \, k\Omega$. The voltage gain of the transistor will be

$Assertion$ : In common base configuration, the current gain of the transistor is less than unity.
$Reason$ : The collector terminal is reverse biased for amplification.

An $n-p-n$ transistor can be considered to be equivalent to two diodes connected back-to-back. Which of the following figures correctly represents this equivalent circuit?

In common emitter mode of a transistor, the current gain is $8$. The input impedance is $25 \, k\Omega$ and load resistance is $75 \, k\Omega$. The power gain is