In which of the following arrangements is the given sequence not strictly according to the property indicated against it?

  • A
    $HF < HCl < HBr < HI$ : increasing acidic strength
  • B
    $H_2O < H_2S < H_2Se < H_2Te$ : increasing $pK_a$ values
  • C
    $NH_3 < PH_3 < AsH_3 < SbH_3$ : increasing acidic character
  • D
    $CO_2 < SiO_2 < SnO_2 < PbO_2$ : increasing oxidising power

Explore More

Similar Questions

Which of the following dissociates to give ${H^{+}}$ most easily?

What is obtained by the reaction of concentrated $H_2SO_4$ with $PCl_5$?

$A$ sulphate of a metal $(A)$ on heating evolves two gases $(B)$ and $(C)$ and an oxide $(D).$ Gas $(B)$ turns $K_2Cr_2O_7$ paper green while gas $(C)$ forms a trimer in which there is no $S-S$ bond. Compound $(D)$ with $HCl$ reacts to form a compound $(E)$ which exists as a dimer. Compounds $(A)$,$(B)$,$(C)$,$(D)$ and $(E)$ are respectively:

Difficult
View Solution

$H_2S$ is more acidic than $H_2O$,due to

Acidity of diprotic acids in aqueous solutions increases in the order:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo