In which of the following compounds does nitr | vedclass

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(A) To find the oxidation state of nitrogen $(x)$ in each compound:$1. N_2H_4: 2x + 4(+1) = 0$ $\Rightarrow 2x = -4$ $\Rightarrow x = -2$$2. NH_3: x +

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$N_3H$

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(A) To find the oxidation state of nitrogen $(x)$ in each compound:$1. N_2H_4: 2x + 4(+1) = 0$ $\Rightarrow 2x = -4$ $\Rightarrow x = -2$$2. NH_3: x + 3(+1) = 0 \Rightarrow x = -3$$3. N_3H: 3x + 1(+1) = 0$ $\Rightarrow 3x = -1$ $\Rightarrow x = -1/3$$4. NH_2OH: x + 2(+1) + (-2) + (+1) = 0$ $\Rightarrow x + 1 = 0$ $\Rightarrow x = -1$Comparing the values: $-3 The highest oxidation state is $-1/3$,which corresponds to $N_3H$.

In which of the following compounds does nitrogen exhibit the highest oxidation state?

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