In which of the following ionization processe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To determine the change in bond energy and magnetic behavior,we analyze the Molecular Orbital Theory $(MOT)$ configurations:$1$. For $NO$ ($15$ el

Vedclass · Accepted Answer

$NO \rightarrow NO^+$

Vedclass · Answer

(C) To determine the change in bond energy and magnetic behavior,we analyze the Molecular Orbital Theory $(MOT)$ configurations:$1$. For $NO$ ($15$ electrons): Configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1$. It is paramagnetic due to the unpaired electron in the $\pi^*$ orbital. Bond order = $(10-5)/2 = 2.5$.$2$. For $NO^+$ ($14$ electrons): Configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2$. It is diamagnetic as all electrons are paired. Bond order = $(10-4)/2 = 3.0$.Since the bond order increases from $2.5$ to $3.0$,the bond energy increases,and the magnetic behavior changes from paramagnetic to diamagnetic.

In which of the following ionization processes does the bond energy increase and the magnetic behaviour change from paramagnetic to diamagnetic?

Similar Questions

If $(2, -1, 3)$ is the foot of the perpendicular drawn from the origin to a plane, then the equation of that plane is

The perimeter of a sector is a constant. If its area is to be maximum,the sectorial angle is:

The element with atomic number $12$ belongs to ......... group and ......... period.

If the image of $\left(\frac{-7}{5}, \frac{-6}{5}\right)$ in a line is $(1, 2)$,then the equation of the line is

$\log _4 2 - \log _8 2 + \log _{16} 2 - \dots$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module