In which of the following is the keto form mo | vedclass

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(D) The keto-enol tautomerism equilibrium depends on the stability of the keto and enol forms. $(a)$ Cyclobutane$-1,2-$dione: The enol form would be a

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All of these

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(D) The keto-enol tautomerism equilibrium depends on the stability of the keto and enol forms. $(a)$ Cyclobutane$-1,2-$dione: The enol form would be anti-aromatic,which is highly unstable. Thus,the keto form is much more stable. $(b)$ $2-$tert-butylcyclohexane$-1,3-$dione: The enol form experiences a severe steric clash between the bulky tert-butyl group and the hydroxyl group,making the keto form more stable. $(c)$ Bicyclo[$2.2$.$1$]heptane$-2,5-$dione: The formation of the enol form would require a double bond at the bridgehead position,which violates Bredt's rule. Therefore,the keto form is more stable. Since all three cases favor the keto form,the correct answer is $(D)$.

List-$I$ (Pair of Compounds)	List-$II$ (Isomerism)
$A$. $n$-propanol and Isopropanol	$(I)$ Metamerism
$B$. Methoxypropane and ethoxyethane	$(II)$ Chain Isomerism
$C$. Propanone and propanal	$(III)$ Position Isomerism
$D$. Neopentane and Isopentane	$(IV)$ Functional Isomerism

In which of the following is the keto form more dominating than the enol form?

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