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(B) The central atom in $SO_2$ is $S$. The number of hybrid orbitals is calculated as $1/2(V + M - C + A)$,where $V$ is the number of valence electron

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$SO_2$

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(B) The central atom in $SO_2$ is $S$. The number of hybrid orbitals is calculated as $1/2(V + M - C + A)$,where $V$ is the number of valence electrons,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.For $SO_2$: $V = 6$ (for $S$),$M = 0$ (since $O$ is divalent).Number of hybrid orbitals = $1/2(6 + 0) = 3$.$3$ hybrid orbitals correspond to $sp^2$ hybridization.

In which of the following molecules does the central atom use $sp^2$ hybrid orbitals to form covalent bonds?

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