In which of the following reactions is the Sa | vedclass

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(D) The $Saytzeff$ product is the more substituted alkene,which is generally favored by small,strong bases.In option $D$,the reaction of $2-bromo-2-me

Vedclass · Accepted Answer

$CH_3-CH_2-CH_2-C(Br)(CH_3)_2 \xrightarrow[\Delta]{CH_3OK}$

Vedclass · Answer

(D) The $Saytzeff$ product is the more substituted alkene,which is generally favored by small,strong bases.In option $D$,the reaction of $2-bromo-2-methylpentane$ with $CH_3OK$ (a small base) leads to $2-methylpent-2-ene$ as the major product because it is the more substituted (more stable) alkene.Option $A$ involves the $Hofmann$ elimination of a quaternary ammonium salt.Option $B$ involves the $Hofmann$ elimination of a fluoride leaving group.Option $C$ uses $t-BuOK$,a bulky base,which favors the less substituted $Hofmann$ product.

In which of the following reactions is the $Saytzeff$ alkene the major product?

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