In which of the following,the compounds are c | vedclass

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(B) The boiling point of a compound depends on the strength of intermolecular forces,primarily hydrogen bonding and molecular mass. $H_2O$ has the hig

Vedclass · Accepted Answer

$H_2O > HF > NH_3 > PH_3$

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(B) The boiling point of a compound depends on the strength of intermolecular forces,primarily hydrogen bonding and molecular mass. $H_2O$ has the highest boiling point $(373 \ K)$ because each $H_2O$ molecule can form four hydrogen bonds. $HF$ has a high boiling point $(293 \ K)$ due to strong hydrogen bonding,but it forms fewer hydrogen bonds per molecule than $H_2O$. $NH_3$ has a boiling point of $240 \ K$ due to weaker hydrogen bonding compared to $HF$. $PH_3$ has the lowest boiling point $(185 \ K)$ as it does not exhibit hydrogen bonding and relies only on weak van der Waals forces. Thus,the correct decreasing order is $H_2O > HF > NH_3 > PH_3$.

In which of the following,the compounds are correctly arranged in the decreasing order of boiling points?

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