In which pair is the second ion more stable t | vedclass

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(B) Stability is determined by aromaticity,resonance,and inductive effects.$(i)$ Cyclopropenyl cation is aromatic ($2\pi$ electrons),while cyclopropen

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$(ii)$ and $(iii)$

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(B) Stability is determined by aromaticity,resonance,and inductive effects.$(i)$ Cyclopropenyl cation is aromatic ($2\pi$ electrons),while cyclopropenyl anion is anti-aromatic ($4\pi$ electrons). Thus,the first is more stable.$(ii)$ Cyclopentadienyl cation is anti-aromatic ($4\pi$ electrons),while cyclopentadienyl anion is aromatic ($6\pi$ electrons). Thus,the second is more stable.$(iii)$ Cycloheptatrienyl cation is aromatic ($6\pi$ electrons),while cycloheptatrienyl anion is anti-aromatic ($8\pi$ electrons). Thus,the first is more stable.$(iv)$ The carbocation with the $-OH$ group is stabilized by resonance (lone pair donation),whereas the carbocation with the $-CH_3$ group is stabilized only by hyperconjugation and inductive effect. Thus,the first is more stable.Therefore,only in pair $(ii)$ is the second ion more stable than the first.

List-$I$ (Carbocation)	List-$II$ (Type)
$A$. $CH_3-C^{+}(CH_3)-CH_3$	$I$. Secondary carbocation
$B$. $CH_3-C^{+}H-CH_3$	$II$. Methyl carbocation
$C$. $CH_3-CH_2^+$	$III$. Primary carbocation
$D$. $CH_3^+$	$IV$. Tertiary carbocation

In which pair is the second ion more stable than the first?

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List-$I$ (Carbocation) List-$II$ (Type)

$A$. $CH_3-C^{+}(CH_3)-CH_3$ $I$. Secondary carbocation

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$D$. $CH_3^+$ $IV$. Tertiary carbocation

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