(B) The formula for the position of the $n^{th}$ bright fringe (maxima) in Young's double slit experiment is given by $x_n = \frac{n \lambda D}{d}$.Gi

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(B) The formula for the position of the $n^{th}$ bright fringe (maxima) in Young's double slit experiment is given by $x_n = \frac{n \lambda D}{d}$.Given values are:$\lambda = 5000\;\mathring{A} = 5000 \times 10^{-10}\;m = 5 \times 10^{-7}\;m$$d = 0.2\;mm = 0.2 \times 10^{-3}\;m = 2 \times 10^{-4}\;m$$D = 200\;cm = 2\;m$For the third maximum, $n = 3$.Substituting these values into the formula:$x_3 = \frac{3 \times (5 \times 10^{-7}\;m) \times (2\;m)}{2 \times 10^{-4}\;m}$$x_3 = \frac{30 \times 10^{-7}}{2 \times 10^{-4}}\;m = 15 \times 10^{-3}\;m = 1.5 \times 10^{-2}\;m = 1.5\;cm$.Therefore, the third maximum is at $x = 1.5\;cm$.

Class 12 Physics Wave Optics Young's Double Slit Experiment (YDSE)

Medium

In Young's double slit experiment, carried out with light of wavelength $\lambda = 5000\;\mathring{A}$, the distance between the slits is $d = 0.2\;mm$ and the screen is at $D = 200\;cm$ from the slits. The central maximum is at $x = 0$. The third maximum (taking the central maximum as the zeroth maximum) will be at $x$ equal to......$cm$.

AIPMT 1992 All AIPMT

A
$1.67$
B
$1.5$
C
$0.5$
D
$5$

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Wave Optics

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Young's Double Slit Experiment (YDSE)

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In Young's double slit experiment,the distance between two sources is $0.1 \, mm$. The distance of the screen from the sources is $20 \, cm$. The wavelength of light used is $5460 \, \mathring{A}$. The angular position of the first dark fringe is: (in $^\circ$)

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The intensity of each source in Young's double slit experiment is $I_0$. The distance between the slits is $d = 5\lambda$,where $\lambda$ is the wavelength of the monochromatic light used. What will be the intensity of light in front of one of the slits on a screen (where the slit and screen are at a distance $D = 10d$)?

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The graph shows the variation of fringe width $(X)$ versus the distance of the screen from the plane of the slits $(D)$ in Young's double-slit experiment (keeping other parameters constant,where $d$ is the distance between the slits). The wavelength of light used can be calculated as:

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If the path difference of the point on the screen from two coherent sources is constant, what is the shape of the trajectory of the point on the screen?

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In a Young's double slit experiment,the distance between the two identical slits is $6.1$ times larger than the slit width. Then the number of intensity maxima observed within the central maximum of the single slit diffraction pattern is

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