In Young's double slit experiment,the distance between the sources is $1 \ mm$ and the distance between the screen and the source is $1 \ m$. If the fringe width on the screen is $0.06 \ cm$,then $\lambda = \dots \mathring{A}$.

  • A
    $6000$
  • B
    $4000$
  • C
    $1200$
  • D
    $2400$

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