In Young's double slit experiment,the distanc | vedclass

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(A) The formula for the position of the $n^{th}$ bright fringe is given by $x_n = \frac{n \lambda D}{d}$.Given values are:Slit separation $d = 1 \,mm

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$5000$

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(A) The formula for the position of the $n^{th}$ bright fringe is given by $x_n = \frac{n \lambda D}{d}$.Given values are:Slit separation $d = 1 \,mm = 1 	imes 10^{-3} \,m$.Distance to screen $D = 1 \,m$.Position of $10^{th}$ fringe $x_{10} = 5 \,mm = 5 	imes 10^{-3} \,m$.Order of fringe $n = 10$.Substituting these values into the formula:$5 	imes 10^{-3} = \frac{10 	imes \lambda 	imes 1}{1 	imes 10^{-3}}$$\lambda = \frac{5 	imes 10^{-3} 	imes 10^{-3}}{10} = 5 	imes 10^{-7} \,m$.Converting to $\mathring A$:$\lambda = 5 	imes 10^{-7} 	imes 10^{10} \, \mathring A = 5000 \, \mathring A$.

In Young's double slit experiment,the distance between the slits is $1 \,mm$ and the distance between the slit and the screen is $1 \,m$. If the $10^{th}$ fringe is $5 \,mm$ away from the central bright fringe,then the wavelength of the light used will be.....$\mathring A$.

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