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(D) The formula for fringe width $(\beta)$ in Young's double slit experiment is given by: $\beta = \frac{\lambda D}{d}$.Here, $\beta = 4 \, mm = 4 	i

Vedclass · Accepted Answer

$1 \, m$

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(D) The formula for fringe width $(\beta)$ in Young's double slit experiment is given by: $\beta = \frac{\lambda D}{d}$.Here, $\beta = 4 \, mm = 4 	imes 10^{-3} \, m$, $\lambda = 4 	imes 10^{-7} \, m$, and $d = 0.1 \, mm = 0.1 	imes 10^{-3} \, m$.Substituting these values into the formula:$4 	imes 10^{-3} = \frac{(4 	imes 10^{-7}) 	imes D}{0.1 	imes 10^{-3}}$$D = \frac{(4 	imes 10^{-3}) 	imes (0.1 	imes 10^{-3})}{4 	imes 10^{-7}}$$D = \frac{0.4 	imes 10^{-6}}{4 	imes 10^{-7}} = 0.1 	imes 10^1 = 1 \, m$.Therefore, the distance between the screen and the slit is $1 \, m$.

In Young's double slit experiment, the distance between the two slits is $0.1 \, mm$ and the wavelength of light used is $4 \times 10^{-7} \, m$. If the width of the fringe on the screen is $4 \, mm$, the distance between the screen and the slit is:

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