In the molecule $CH_2=C=CH-CH_3$ (where the atoms are numbered $1, 2, 3,$ and $4$ respectively),the hybridization of carbon $1, 2, 3,$ and $4$ are:

  • A
    $sp^2, sp, sp^2, sp^3$
  • B
    $sp^2, sp^2, sp^2, sp^3$
  • C
    $sp^2, sp^2, sp, sp^3$
  • D
    $sp^2, sp^3, sp^2, sp^3$

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Similar Questions

The base strength order of $H_3C-CH_2^-$ $(i)$,$H_2C=CH^-$ $(ii)$,and $HC \equiv C^-$ $(iii)$ is:

How many $(i)$ $sp^{2}$ hybridised carbon atoms and $(ii)$ $\pi$ bonds are present in the following compound?

$(a)$ Discuss the concept of hybridization. What are its different types in a carbon atom.
$(b)$ What is the type of hybridization of carbon atoms marked with a star in the following structures:
$(a)$ $\overset{*}{C}H_2 = CH - C(=O)OH$
$(b)$ $CH_3 - \overset{*}{C}H_2 - OH$
$(c)$ $CH_3 - CH_2 - \overset{*}{C}H = O$
$(d)$ $\overset{*}{C}H_3 - CH = CH - CH_3$
$(e)$ $CH_3 - \overset{*}{C} \equiv CH$

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Arrange the following compounds in decreasing order of acidity: $H_{2}O, ROH, HC \equiv CH$

In the structure $CH_2 = CH - C \equiv CH$,what are the hybridization states of the carbon atoms that are connected to each other by a single bond?

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