Which of the following is the incorrect order | vedclass

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(A) In $CF_4$,$CCl_4$,and $CBr_4$,all are tetrahedral with bond angles of $109.5^\circ$. Thus,the order $\alpha > \beta > \gamma$ is incorrect as they

Vedclass · Accepted Answer

$CF_4 > CCl_4 > CBr_4$ (where $\angle XCX$ is the bond angle and $X$ is a halogen atom)

Vedclass · Answer

(A) In $CF_4$,$CCl_4$,and $CBr_4$,all are tetrahedral with bond angles of $109.5^\circ$. Thus,the order $\alpha > \beta > \gamma$ is incorrect as they are equal.In $NCl_3$,$PCl_3$,and $AsCl_3$,the bond angle decreases as the electronegativity of the central atom decreases $(N > P > As)$,so $NCl_3 > PCl_3 > AsCl_3$ is correct.In $SOF_2$,the $S=O$ double bond exerts more repulsion than the $S-F$ single bonds,making $\angle FSO > \angle FSF$ correct.In $NO_2^+$,$NO_2$,and $NO_2^-$,the bond angles are $180^\circ$,$134^\circ$,and $115^\circ$ respectively,so $NO_2^+ > NO_2 > NO_2^-$ is correct.Therefore,option $A$ is the incorrect order.

Which of the following is the incorrect order of bond angle?

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