Which of the following statements is incorrec | vedclass

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(D) $A)$ Due to the small size and high charge density of $Be^{2+}$,its polarizing power is high,which leads to the sharing of electrons between $Be$

Vedclass · Accepted Answer

The hybrid state of $Be$ in solid $BeCl_2$ is $sp^2$

Vedclass · Answer

(D) $A)$ Due to the small size and high charge density of $Be^{2+}$,its polarizing power is high,which leads to the sharing of electrons between $Be$ and $Cl$. This gives $BeCl_2$ significant covalent character.$B)$ The $Be$ atom has only $4$ electrons in its valence shell,which does not satisfy the octet rule. Therefore,it is an electron-deficient molecule.$C)$ $BeCl_2$ exists as a polymeric chain in the solid state and can form a dimer in the vapor phase.$D)$ In solid $BeCl_2$,the $Be$ atom is $sp^3$ hybridized (due to coordinate bonding in the polymeric structure),and in the monomeric gaseous state,it is $sp$ hybridized. Thus,the statement that it is $sp^2$ is incorrect.

Which of the following statements is incorrect?

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