Increasing order of ionic size for the ions,F | vedclass

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(B) The given ions $O^{2-}$,$F^{-}$,$Na^{+}$,and $Al^{3+}$ are isoelectronic species,as each contains $10$ electrons.For isoelectronic species,the ion

Vedclass · Accepted Answer

$Al^{3+} < Na^{+} < F^{-} < O^{2-}$

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(B) The given ions $O^{2-}$,$F^{-}$,$Na^{+}$,and $Al^{3+}$ are isoelectronic species,as each contains $10$ electrons.For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number,$Z$) increases.The atomic numbers are: $O (Z=8)$,$F (Z=9)$,$Na (Z=11)$,and $Al (Z=13)$.Since the nuclear charge increases in the order $O F^{-} > Na^{+} > Al^{3+}$.Therefore,the increasing order of ionic size is $Al^{3+} < Na^{+} < F^{-} < O^{2-}$.

Increasing order of ionic size for the ions,$F^{-}$,$O^{2-}$,$Na^{+}$,$Al^{3+}$ is :-

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