The increasing order of the rate of reaction | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction with $Br_2 / AlCl_3$ is an electrophilic aromatic substitution reaction. The rate of this reaction depends on the electron density of

Vedclass · Accepted Answer

$iii < i < ii < iv$

Vedclass · Answer

(A) The reaction with $Br_2 / AlCl_3$ is an electrophilic aromatic substitution reaction. The rate of this reaction depends on the electron density of the aromatic ring. Higher electron density increases the rate of reaction.$(i)$ The ring has a weak electron-withdrawing group attached.(ii) The ring has a strong electron-donating group $(-OH)$ and a weak electron-donating group.(iii) The ring has a strong electron-withdrawing carbonyl group $(C=O)$.(iv) The ring has a strong electron-donating group $(-OH)$ and an oxygen atom that provides additional electron density via resonance.Comparing the electronic effects:- (iii) has a strong electron-withdrawing group,making it the slowest.- $(i)$ has a weak electron-withdrawing effect.- (ii) has strong electron-donating groups.- (iv) has the strongest electron-donating effect due to the additional oxygen atom.Thus,the increasing order of the rate of reaction is $iii < i < ii < iv$.

The increasing order of the rate of reaction with $Br_2 / AlCl_3$ is:

Similar Questions

Which of the following substances is the most volatile?

Select the correct decreasing order of acid strength for the following compounds: $(a)$ $Ethanol$ $(b)$ $2-Methylpropan-2-ol$ $(c)$ $Phenol$ $(d)$ $p-Nitrophenol$.

In the reaction $C_6H_5 - X \xleftarrow[HNO_2]{Cu} C_6H_5N_2Cl \xrightarrow[\Delta]{Water} \phi - Y$,what are $X$ and $Y$ respectively?

The major products $X$ and $Y$ in the following sequence of transformations are:

Which reaction is used to prepare $2$-hydroxybenzaldehyde from phenol?

Vedclass Test Series

Exam Paper Generator

Online Exam Module