(B) $3! = 1 \times 2 \times 3 = 6$$4! = 1 \times 2 \times 3 \times 4 = 24$$\therefore 3! + 4! = 6 + 24 = 30$$7! = 1 \times 2 \times 3 \times 4 \times

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(B) $3! = 1 \times 2 \times 3 = 6$$4! = 1 \times 2 \times 3 \times 4 = 24$$\therefore 3! + 4! = 6 + 24 = 30$$7! = 1 \times 2 \times 3 \times 4 \times 5 \times 6 \times 7 = 5040$$\therefore 3! + 4! \neq 7!$

Class 11 Mathematics Permutation and Combination Definition of permutation, Number of permutations with or without repetition, Conditional permutations

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Is $3! + 4! = 7!$?

A
Yes
B
No
C
Cannot be determined
D
None of these

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Permutation and Combination

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Definition of permutation, Number of permutations with or without repetition, Conditional permutations

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MediumTS EAMCET 2018

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Is $3! + 4! = 7!$?

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The number of integers greater than $3000$ that can be formed by using any number of digits from the set $\{0, 1, 2, 3, 4, 5\}$ without repetition is:

How many permutations of the letters of the word $ENDEANOEL$ are there such that the last five positions do not contain $D, L,$ or $N$?

Given $4$ flags of different colours,how many different signals can be generated,if a signal requires the use of $2$ flags one below the other?

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