Is $0.2$ a root of the equation $x^{2}-0.4=0$? Justify.
(B) To determine if $0.2$ is a root of the equation $x^{2}-0.4=0$,we substitute $x = 0.2$ into the equation.
Substituting $x = 0.2$ into the left-hand side $(LHS)$ gives:
$(0.2)^{2} - 0.4 = 0.04 - 0.4 = -0.36$.
Since the result is $-0.36$ and not $0$,the value $0.2$ does not satisfy the equation.
Therefore,$0.2$ is not a root of the equation $x^{2}-0.4=0$.
Substituting $x = 0.2$ into the left-hand side $(LHS)$ gives:
$(0.2)^{2} - 0.4 = 0.04 - 0.4 = -0.36$.
Since the result is $-0.36$ and not $0$,the value $0.2$ does not satisfy the equation.
Therefore,$0.2$ is not a root of the equation $x^{2}-0.4=0$.
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