It costs Rs. 2200 to paint the inner curved s | vedclass

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(A) Given:Total cost of painting $= Rs. 2200$Rate of painting $= Rs. 20 \, 	ext{per} \, m^2$Depth (height) of the vessel $(h)$ $= 10 \, m$First, calc

Vedclass · Accepted Answer

$1.75$

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(A) Given:Total cost of painting $= Rs. 2200$Rate of painting $= Rs. 20 \, 	ext{per} \, m^2$Depth (height) of the vessel $(h)$ $= 10 \, m$First, calculate the inner curved surface area $(CSA)$ of the cylindrical vessel:$CSA = \frac{	ext{Total cost}}{	ext{Rate}} = \frac{2200}{20} = 110 \, m^2$The formula for the curved surface area of a cylinder is $CSA = 2 \pi rh$.Substituting the known values:$110 = 2 	imes \frac{22}{7} 	imes r 	imes 10$Solving for $r$:$110 = \frac{440}{7} 	imes r$$r = \frac{110 	imes 7}{440}$$r = \frac{7}{4} = 1.75 \, m$Thus, the radius of the base is $1.75 \, m$.

It costs $Rs. 2200$ to paint the inner curved surface of a cylindrical vessel $10 \, m$ deep. If the cost of painting is at the rate of $Rs. 20$ per $m^2$, find the radius of the base. (in $m$)

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