Justify the output waveform $(Y)$ of the $OR$ gate for the following inputs $A$ and $B$ given in the figure.

(N/A) For an $OR$ gate,the output $Y = A + B$. This means the output is $1$ if either input $A$ or $B$ is $1$,and $0$ only if both inputs are $0$.
$1$. For $t < t_{1}$: $A=0, B=0$,so $Y = 0 + 0 = 0$.
$2$. For $t_{1}$ to $t_{2}$: $A=1, B=0$,so $Y = 1 + 0 = 1$.
$3$. For $t_{2}$ to $t_{3}$: $A=1, B=1$,so $Y = 1 + 1 = 1$.
$4$. For $t_{3}$ to $t_{4}$: $A=0, B=1$,so $Y = 0 + 1 = 1$.
$5$. For $t_{4}$ to $t_{5}$: $A=0, B=0$,so $Y = 0 + 0 = 0$.
$6$. For $t_{5}$ to $t_{6}$: $A=1, B=0$,so $Y = 1 + 0 = 1$.
$7$. For $t > t_{6}$: $A=0, B=1$,so $Y = 0 + 1 = 1$.
Thus,the output waveform $Y$ follows the logic of the $OR$ gate as shown in the figure.