Krypton (_{36}Kr) has the electronic configur | vedclass

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(D) The $37^{th}$ electron will enter the $5s$ subshell.According to the Aufbau principle,electrons fill orbitals in the order of increasing energy.Fo

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$5s$

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(D) The $37^{th}$ electron will enter the $5s$ subshell.According to the Aufbau principle,electrons fill orbitals in the order of increasing energy.For the $4p$ orbital,$n=4$ and $l=1$,so $(n+l) = 4+1 = 5$.For the $5s$ orbital,$n=5$ and $l=0$,so $(n+l) = 5+0 = 5$.When $(n+l)$ values are equal,the orbital with the lower value of $n$ is filled first. Since $4p$ has $n=4$ and $5s$ has $n=5$,$4p$ is filled before $5s$.Therefore,after the $4p^6$ configuration is complete,the next electron $(37^{th})$ enters the $5s$ orbital.

Krypton $(_{36}Kr)$ has the electronic configuration $[Ar] 4s^2 3d^{10} 4p^6$. The $37^{th}$ electron will go into which of the following subshells?

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