Difficult
Lattice enthalpy for $NaCl$ is $+788 \ kJ \ mol^{-1}$ and $\Delta H_{\text{hyd}}^{\circ} = -784 \ kJ \ mol^{-1}$. The enthalpy of solution of $NaCl$ is:
- A$+572 \ kJ \ mol^{-1}$
- B$+4 \ kJ \ mol^{-1}$
- C$-572 \ kJ \ mol^{-1}$
- D$-4 \ kJ \ mol^{-1}$
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