Let v and a denote the velocity and accelerat | vedclass

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Question

(A) The speed of a particle is the magnitude of its velocity vector $v$. The rate of change of speed is given by the tangential component of accelerat

Vedclass · Accepted Answer

The speed of the particle decreases when $v \cdot a < 0$.

Vedclass · Answer

(A) The speed of a particle is the magnitude of its velocity vector $v$. The rate of change of speed is given by the tangential component of acceleration,$a_t = \frac{dv}{dt} = \frac{a \cdot v}{|v|}$.$1$. If $v \cdot a > 0$,the angle between velocity and acceleration is acute $(0^\circ \le 	heta $2$. If $v \cdot a $3$. The cross product $v 	imes a$ relates to the change in direction of velocity (centripetal acceleration),not the change in speed in one-dimensional motion. Thus,option $(a)$ is correct.

Let $v$ and $a$ denote the velocity and acceleration respectively of a particle in one-dimensional motion. Which of the following statements is correct?

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