Let A = begin{bmatrix} 2 & 4 3 & 2 end{bmatr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To find the product $BA$,we multiply matrix $B$ by matrix $A$ as follows:$BA = \begin{bmatrix} 1 & 3 \ -2 & 5 \end{bmatrix} \begin{bmatrix} 2 & 4

Vedclass · Accepted Answer

$\begin{bmatrix} 11 & 10 \ 11 & 2 \end{bmatrix}$

Vedclass · Answer

(A) To find the product $BA$,we multiply matrix $B$ by matrix $A$ as follows:$BA = \begin{bmatrix} 1 & 3 \ -2 & 5 \end{bmatrix} \begin{bmatrix} 2 & 4 \ 3 & 2 \end{bmatrix}$Performing matrix multiplication:$BA = \begin{bmatrix} (1 	imes 2) + (3 	imes 3) & (1 	imes 4) + (3 	imes 2) \ (-2 	imes 2) + (5 	imes 3) & (-2 	imes 4) + (5 	imes 2) \end{bmatrix}$$BA = \begin{bmatrix} 2 + 9 & 4 + 6 \ -4 + 15 & -8 + 10 \end{bmatrix}$$BA = \begin{bmatrix} 11 & 10 \ 11 & 2 \end{bmatrix}$

Let $A = \begin{bmatrix} 2 & 4 \\ 3 & 2 \end{bmatrix}$,$B = \begin{bmatrix} 1 & 3 \\ -2 & 5 \end{bmatrix}$,and $C = \begin{bmatrix} -2 & 5 \\ 3 & 4 \end{bmatrix}$. Find $BA$.

Similar Questions

If a matrix has $18$ elements,what are the possible orders it can have? What,if it has $5$ elements?

$A$ square matrix $A = [a_{ij}]$ in which $a_{ij} = 0$ for $i \neq j$ and $a_{ij} = k$ (constant) for $i = j$ is called a

If $A$ is a nilpotent matrix of index $2$,then $A(I_2+A)^{51}$ is equal to (where $I_2$ is the identity matrix of order $2$)

If $A = \begin{bmatrix} \cos \alpha & -\sin \alpha \\ \sin \alpha & \cos \alpha \end{bmatrix}$ and $B = \begin{bmatrix} \cos \beta & -\sin \beta \\ \sin \beta & \cos \beta \end{bmatrix}$,then the correct relation is

If $A = \begin{bmatrix} 1 & 1 \\ 0 & 1 \end{bmatrix}$ and $B = \begin{bmatrix} \frac{\sqrt{3}}{2} & \frac{1}{2} \\ -\frac{1}{2} & \frac{\sqrt{3}}{2} \end{bmatrix}$,then $(BB^TA)^5$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module