Let $f$ be a differentiable function in $\left(0, \frac{\pi}{2}\right)$. If $\int\limits_{\cos x}^{1} t^{2} f(t) d t = \sin^{3} x + \cos x - 1$,then $\frac{1}{\sqrt{3}} f^{\prime}\left(\frac{1}{\sqrt{3}}\right)$ is equal to

  • A
    $6 - 9\sqrt{2}$
  • B
    $\frac{9}{\sqrt{2}} - 6$
  • C
    $\frac{9}{2} - 6\sqrt{2}$
  • D
    $6 - \frac{9}{\sqrt{2}}$

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