Let Delta, nabla in {wedge, vee} be such that | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To determine which combination results in a tautology,we evaluate the truth table for each case:$1$. For $\Delta=\wedge, 
abla=\vee$: The express

Vedclass · Accepted Answer

$\Delta=\vee, 
abla=\vee$

Vedclass · Answer

(C) To determine which combination results in a tautology,we evaluate the truth table for each case:$1$. For $\Delta=\wedge, 
abla=\vee$: The expression is $(p ightarrow q) \wedge (p \vee q)$. If $p=T, q=F$,then $(T ightarrow F) \wedge (T \vee F) = F \wedge T = F$. Not a tautology.$2$. For $\Delta=\vee, 
abla=\wedge$: The expression is $(p ightarrow q) \vee (p \wedge q)$. If $p=T, q=F$,then $(T ightarrow F) \vee (T \wedge F) = F \vee F = F$. Not a tautology.$3$. For $\Delta=\vee, 
abla=\vee$: The expression is $(p ightarrow q) \vee (p \vee q)$. - If $p=T, q=T$: $T \vee T = T$- If $p=T, q=F$: $F \vee T = T$- If $p=F, q=T$: $T \vee T = T$- If $p=F, q=F$: $T \vee F = T$Since all values are $T$,this is a tautology.$4$. For $\Delta=\wedge, 
abla=\wedge$: The expression is $(p ightarrow q) \wedge (p \wedge q)$. If $p=F, q=F$,then $T \wedge F = F$. Not a tautology.Thus,the correct option is $\Delta=\vee, 
abla=\vee$.

Let $\Delta, \nabla \in \{\wedge, \vee\}$ be such that $( p \rightarrow q ) \Delta ( p \nabla q )$ is a tautology. Then

Similar Questions

If $p$ and $q$ each have truth value $F$,then the truth values of the statement patterns $(\sim p \vee q) \leftrightarrow \sim(p \wedge q)$ and $\sim p \leftrightarrow (p \rightarrow \sim q)$ respectively are

Which of the following statements is true?

If $p \rightarrow (q \vee r)$ is false,then what are the truth values of $p, q, r$ respectively?

If $p, q, r, s$ are statements,where:
$p: A^2-B^2=(A-B)(A+B)$ where $A, B$ are matrices and $AB \neq BA$
$q: 5 \leqslant 5$
$r: { }^8 C_1+{ }^8 C_2+{ }^8 C_3+\ldots+{ }^8 C_8=256$
$s: \text{Maximum value of } { }^8 C_r \text{ is } 70$
Which of the following statements has a truth value of true?

$(p \wedge \sim q \wedge \sim r) \vee (\sim p \wedge q \wedge \sim r) \vee (\sim p \wedge \sim q \wedge r)$ is equivalent to-

Vedclass Test Series

Exam Paper Generator

Online Exam Module