Let A = {1, 2, 3, 4, 5} and B = {2, 3, 6, 7}. | vedclass

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(C) The intersection of two Cartesian products is given by the formula $(A 	imes B) \cap (B 	imes A) = (A \cap B) 	imes (B \cap A)$.Given $A = \{1,

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$4$

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(C) The intersection of two Cartesian products is given by the formula $(A 	imes B) \cap (B 	imes A) = (A \cap B) 	imes (B \cap A)$.Given $A = \{1, 2, 3, 4, 5\}$ and $B = \{2, 3, 6, 7\}$.The intersection of the sets is $A \cap B = \{2, 3\}$.Thus,$(A \cap B) 	imes (B \cap A) = \{2, 3\} 	imes \{2, 3\} = \{(2, 2), (2, 3), (3, 2), (3, 3)\}$.The number of elements in this set is $2 	imes 2 = 4$.

Let $A = \{1, 2, 3, 4, 5\}$ and $B = \{2, 3, 6, 7\}$. Then the number of elements in $(A \times B) \cap (B \times A)$ is

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