Let $p, q, r$ be three statements,then $[p$ $\rightarrow (q$ $\rightarrow r)] \leftrightarrow [(p \wedge q)$ $\rightarrow r]$ is

The statement $(p$ $\Rightarrow q) \vee (p$ $\Rightarrow r)$ is $NOT$ equivalent to:

Consider the following statements:
$r: \text{If } p \to q \text{ is false, then } p \lor q \text{ is false.}$
$s: \text{If } p \leftrightarrow q \text{ is false, then } p \lor q \text{ is false.}$
The truth values of $r \to s$ and $s \to r$ are respectively . . . . . .

Statement $-1$: The statement $A \to (B \to A)$ is equivalent to $A \to (A \vee B)$.
Statement $-2$: The statement $\sim [(A \wedge B) \to (\sim A \vee B)]$ is a tautology.

The negation of the statement "If an integer is greater than $4$ and less than $5$, then it is a multiple of $3$" is:

If $\sim p \lor q$ is false, then which of the following is correct?