Let $n$ be the number of liquid drops,each with surface energy $E$. These drops join to form a single drop. In this process:

  • A
    some energy will be absorbed
  • B
    energy absorbed is $[E(n-n^{2/3})]$
  • C
    energy released will be $[E(n-n^{2/3})]$
  • D
    energy released will be $[E(2^{2/3}-1)]$

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