(A) Given the function $f(x) = \frac{|x|}{x}$ for $x \in A$,where $A = \{x \in R, x \neq 0, -4 \leq x \leq 4\}$.If $x > 0$,then $|x| = x$,so $f(x) = \

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(A) Given the function $f(x) = \frac{|x|}{x}$ for $x \in A$,where $A = \{x \in R, x \neq 0, -4 \leq x \leq 4\}$.If $x > 0$,then $|x| = x$,so $f(x) = \frac{x}{x} = 1$.If $x Since $x$ cannot be $0$,the function only takes the values $1$ and $-1$.Therefore,the range of $f$ is $\{1, -1\}$.

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Let $A = \{x \in R, x \neq 0, -4 \leq x \leq 4\}$ and $f: A \rightarrow R$ be defined by $f(x) = \frac{|x|}{x}$ for $x \in A$. Then,the range of $f$ is

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A
$\{1, -1\}$
B
$\{x: 0 \leq x \leq 1\}$
C
$1$
D
$\{x: -4 \leq x \leq 0\}$

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Let $A = \{x \in R, x \neq 0, -4 \leq x \leq 4\}$ and $f: A \rightarrow R$ be defined by $f(x) = \frac{|x|}{x}$ for $x \in A$. Then,the range of $f$ is

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