Let $A$ and $B$ be two events such that $P(A) = \frac{5}{11}$, $P(B) = \frac{2}{11}$, and $P(A \cup B) = \frac{3}{11}$, then $P(A'|B')$ is . . . . . . .
- A$\frac{1}{2}$
- B$\frac{8}{9}$
- C$\frac{3}{5}$
- D$\frac{2}{9}$
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Similar Questions
$A$ biased die is tossed and the respective probabilities for various faces to turn up are given below:
$Face$ $1$ $2$ $3$ $4$ $5$ $6$ $P(F)$ $0.1$ $0.24$ $0.19$ $0.18$ $0.15$ $0.14$
If an even face has turned up,then the probability that it is face $2$ or face $4$ is:
| $Face$ | $1$ | $2$ | $3$ | $4$ | $5$ | $6$ |
| $P(F)$ | $0.1$ | $0.24$ | $0.19$ | $0.18$ | $0.15$ | $0.14$ |
If an even face has turned up,then the probability that it is face $2$ or face $4$ is:
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View Solution$A$ black and a red dice are rolled. Find the conditional probability of obtaining a sum greater than $9,$ given that the black die resulted in a $5$.
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View SolutionFrom a group of $8$ boys and $3$ girls,a committee of $5$ members is to be formed. Find the probability that $2$ particular girls are included in the committee.
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View SolutionIf $P(A) = \frac{1}{2}$ and $P(B) = 0$,then $P(A | B)$ is
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View SolutionGiven that $A$ and $B$ are two events such that $P(B) = \frac{3}{5}$,$P\left(\frac{A}{B}\right) = \frac{1}{2}$,and $P(A \cup B) = \frac{4}{5}$,then $P(A)$ is equal to:
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