Let the circle $S$ which is concentric with the circle $x^2+y^2-2x+ky+4=0$ pass through the point $(3,-2)$. If one of the diameters of $S$ lies along the line $3x-2y+4=0$,then the radius of the circle $S$ is

  • A
    $\frac{\sqrt{149}}{2}$
  • B
    $\sqrt{31}$
  • C
    $\sqrt{38}$
  • D
    $\frac{1}{2}\sqrt{137}$

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