Let the relation R be defined on the set of n | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given the relation $3 a+2 b=27$ where $a, b \in N$ (natural numbers). $2 b = 27 - 3 a$ $b = \frac{3(9 - a)}{2}$ Since $b$ must be a natural number

Vedclass · Accepted Answer

$\{(1, 12), (3, 9), (5, 6), (7, 3)\}$

Vedclass · Answer

(D) Given the relation $3 a+2 b=27$ where $a, b \in N$ (natural numbers). $2 b = 27 - 3 a$ $b = \frac{3(9 - a)}{2}$ Since $b$ must be a natural number,$3(9 - a)$ must be even and positive. For $a = 1, b = \frac{3(8)}{2} = 12$. For $a = 3, b = \frac{3(6)}{2} = 9$. For $a = 5, b = \frac{3(4)}{2} = 6$. For $a = 7, b = \frac{3(2)}{2} = 3$. For $a = 9, b = 0$ (not a natural number). Thus,$R = \{(1, 12), (3, 9), (5, 6), (7, 3)\}$.

Let the relation $R$ be defined on the set of natural numbers $N$ by $a R b$ if $3 a+2 b=27$. Then $R$ is:

Similar Questions

Let $A = \{1, 2, 3\}$ and $B = \{1, 3, 5\}$. If a relation $R$ from $A$ to $B$ is defined as $R = \{(1, 3), (2, 5), (3, 3)\}$,then find the inverse relation ${R^{ - 1}}$.

Let $A = \{1, 2\}$ and $B = \{3, 4\}$. Find the number of relations from $A$ to $B$.

If $n(A) = 2$ and the number of relations from set $A$ to set $B$ is $1024$, then $n(B)$ is

Let $A = \{1, 2, 3, 4\}$,$B = \{1, 5, 9, 11, 15, 16\}$,and $f = \{(1, 5), (2, 9), (3, 1), (4, 5), (2, 11)\}$. Is $f$ a relation from $A$ to $B$? Justify your answer.

Write the relation $R = \{ (x, x^3) : x \text{ is a prime number less than } 10 \}$ in roster form.

Vedclass Test Series

Exam Paper Generator

Online Exam Module