Light enters from air into diamond,which has | vedclass

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(A) Given:Speed of light in air $(c)$ = $3.0 	imes 10^{8} 	ext{ m s}^{-1}$Refractive index of diamond $(n)$ = $2.42$Speed of light in diamond $(v)$

Vedclass · Accepted Answer

$1.24 	imes 10^{8} 	ext{ m s}^{-1}$

Vedclass · Answer

(A) Given:Speed of light in air $(c)$ = $3.0 	imes 10^{8} 	ext{ m s}^{-1}$Refractive index of diamond $(n)$ = $2.42$Speed of light in diamond $(v)$ = ?Formula:The refractive index $(n)$ is defined as the ratio of the speed of light in air $(c)$ to the speed of light in the medium $(v)$:$n = \frac{c}{v}$Calculation:Rearranging the formula to solve for $v$:$v = \frac{c}{n}$$v = \frac{3.0 	imes 10^{8}}{2.42}$$v \approx 1.24 	imes 10^{8} 	ext{ m s}^{-1}$Therefore,the speed of light in diamond is $1.24 	imes 10^{8} 	ext{ m s}^{-1}$.

Light enters from air into diamond,which has a refractive index of $2.42$. Calculate the speed of light in diamond. The speed of light in air is $3.0 \times 10^{8} \text{ m s}^{-1}$.

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