Light from the constellation Virgo is observe | vedclass

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Question

(A) The Doppler effect for light states that the fractional change in wavelength is given by $\frac{\Delta \lambda}{\lambda} = \frac{v}{c}$,where $v$

Vedclass · Accepted Answer

Moving away with velocity $1.2 	imes 10^6 \ m/s$

Vedclass · Answer

(A) The Doppler effect for light states that the fractional change in wavelength is given by $\frac{\Delta \lambda}{\lambda} = \frac{v}{c}$,where $v$ is the relative velocity of the source and $c$ is the speed of light $(3 	imes 10^8 \ m/s)$.Since the wavelength increases (redshift),the constellation is moving away from Earth.Given $\frac{\Delta \lambda}{\lambda} = 0.4\% = 0.004$.Using the formula $v = \frac{\Delta \lambda}{\lambda} 	imes c$:$v = 0.004 	imes 3 	imes 10^8 \ m/s = 1.2 	imes 10^6 \ m/s$.Therefore,the constellation is moving away with a velocity of $1.2 	imes 10^6 \ m/s$.

Light from the constellation Virgo is observed to increase in wavelength by $0.4\%$. With respect to Earth,the constellation is:

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