Light waves producing interference have their | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given the ratio of amplitudes, $\frac{a_1}{a_2} = \frac{3}{2}$.Let $a_1 = 3k$ and $a_2 = 2k$, where $k$ is a constant.The intensity $I$ is proport

Vedclass · Accepted Answer

$25: 1$

Vedclass · Answer

(C) Given the ratio of amplitudes, $\frac{a_1}{a_2} = \frac{3}{2}$.Let $a_1 = 3k$ and $a_2 = 2k$, where $k$ is a constant.The intensity $I$ is proportional to the square of the amplitude, $I \propto a^2$.The ratio of maximum intensity to minimum intensity is given by the formula:$\frac{I_{\max}}{I_{\min}} = \frac{(a_1 + a_2)^2}{(a_1 - a_2)^2}$.Substituting the values:$\frac{I_{\max}}{I_{\min}} = \frac{(3k + 2k)^2}{(3k - 2k)^2} = \frac{(5k)^2}{(k)^2} = \frac{25k^2}{k^2} = \frac{25}{1}$.Thus, the ratio of maximum and minimum intensity is $25: 1$.

Light waves producing interference have their amplitudes in the ratio $3: 2$. The intensity ratio of maximum and minimum of interference fringes is

Similar Questions

If the ratio of the intensities of two waves producing interference is $49: 16$,then the ratio of the resultant maximum intensity to minimum intensity will be

"If you illuminate two pinholes using two lamps, the interference pattern will not be observed" - Explain.

An interference pattern is observed at $P$ due to the superimposition of two rays coming from a source $S$ as shown in the figure. The value of $l$ for which maxima is obtained at $P$ is: ($R$ is a perfectly reflecting surface)

Two monochromatic light beams of intensity $16$ and $9$ units are interfering. The ratio of intensities of bright and dark parts of the resultant pattern is

$n$ identical waves each of intensity $I_0$ interfere with each other. The ratio of maximum intensities if the interference is $(i)$ coherent and $(ii)$ incoherent is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module