Liquid oxygen at 50 K is heated to 300 K at a | vedclass

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(C) The boiling point of oxygen at $1\ atm$ is approximately $90\ K$. When liquid oxygen is heated from $50\ K$ to $300\ K$ at constant pressure, it f

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(C) The boiling point of oxygen at $1\ atm$ is approximately $90\ K$. When liquid oxygen is heated from $50\ K$ to $300\ K$ at constant pressure, it first heats up as a liquid until it reaches its boiling point $(90\ K)$. During this phase, the temperature increases linearly with time because the rate of heating is constant ($Q = mc\Delta T$, so $\frac{dT}{dt} = \frac{P}{mc} = 	ext{constant}$). Once it reaches the boiling point, the temperature remains constant while the liquid undergoes a phase change (boiling) to become gas. This is represented by a horizontal line on the temperature-time graph. After the phase change is complete, the oxygen is in the gaseous state and its temperature continues to rise as it is heated further to $300\ K$. Graph $C$ shows a linear increase in temperature, followed by a constant temperature region during the phase change, and then a linear increase again as a gas. Therefore, graph $C$ is the correct representation.

Column-$I$	Column-$II$
$A$. Conversion of liquid into solid is	$1$. Regelation
$B$. Conversion of liquid into vapour is	$2$. Sublimation
$C$. Conversion of solid into vapour directly is	$3$. Fusion
$D$. Melting of ice caused by pressure is	$4$. Vaporisation

Liquid oxygen at $50\ K$ is heated to $300\ K$ at a constant pressure of $1\ atm$. The rate of heating is constant. Which of the following graphs represents the variation of temperature with time?

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