Liquids A and B form an ideal solution in the | vedclass

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(B) Given: $\chi_A = 0.4$,$\chi_B = 0.6$,$P_A^o = 7 	imes 10^3 \ Pa$,$P_B^o = 12 	imes 10^3 \ Pa$.Total pressure of the solution is $P_T = \chi_A P_

Vedclass · Accepted Answer

$y_A = 0.28$; $y_B = 0.72$

Vedclass · Answer

(B) Given: $\chi_A = 0.4$,$\chi_B = 0.6$,$P_A^o = 7 	imes 10^3 \ Pa$,$P_B^o = 12 	imes 10^3 \ Pa$.Total pressure of the solution is $P_T = \chi_A P_A^o + \chi_B P_B^o$.$P_T = (0.4 	imes 7 	imes 10^3) + (0.6 	imes 12 	imes 10^3) = 2.8 	imes 10^3 + 7.2 	imes 10^3 = 10 	imes 10^3 \ Pa = 10^4 \ Pa$.The mole fraction of $A$ in the vapour phase $(y_A)$ is given by $y_A = \frac{P_A}{P_T} = \frac{\chi_A P_A^o}{P_T}$.$y_A = \frac{0.4 	imes 7 	imes 10^3}{10^4} = \frac{2800}{10000} = 0.28$.The mole fraction of $B$ in the vapour phase is $y_B = 1 - y_A = 1 - 0.28 = 0.72$.

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