Liquids A and B form an ideal solution. If X_ | vedclass

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(B) According to Raoult's law,the partial pressure of a component is given by $P_A = X_A P_A^o$ and $P_B = X_B P_B^o$.In the vapour phase,the mole fra

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$\frac{Y_A}{X_A} > 1$

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(B) According to Raoult's law,the partial pressure of a component is given by $P_A = X_A P_A^o$ and $P_B = X_B P_B^o$.In the vapour phase,the mole fraction $Y_A$ is given by $Y_A = \frac{P_A}{P_A + P_B} = \frac{X_A P_A^o}{X_A P_A^o + X_B P_B^o}$.Given $P_A^o > P_B^o$,the component $A$ is more volatile than $B$.Since $A$ is more volatile,it will be enriched in the vapour phase compared to the liquid phase.Therefore,$Y_A > X_A$,which implies $\frac{Y_A}{X_A} > 1$.

Liquids $A$ and $B$ form an ideal solution. If $X_A$ and $Y_A$ are the mole fractions of $A$ in the solution and in vapour phase in equilibrium,respectively,then (Given $P_A^o > P_B^o$):

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