Liquids have no Poisson's ratio,because

When a wire of length $10 \ m$ is subjected to a force of $100 \ N$ along its length, the lateral strain produced is $0.01 \times 10^{-3} \ m$. The Poisson's ratio was found to be $0.4$. If the area of cross-section of the wire is $0.025 \ m^2$, its Young's modulus is:

$A$ copper wire of cross-sectional area $0.01 \ cm^2$ is under a tension of $22 \ N$. Find the percentage change in the cross-sectional area (Young's modulus of copper $= 1.1 \times 10^{11} \ N \ m^{-2}$ and Poisson ratio $= 0.32$).

$A$ tension of $20 \,N$ is applied to a copper wire of cross-sectional area $0.01 \,cm^2$. The Young's modulus of copper is $1.1 \times 10^{11} \,N/m^2$ and the Poisson's ratio is $0.32$. The decrease in the cross-sectional area of the wire is:

There is no change in the volume of a wire due to change in its length on stretching. The Poisson's ratio of the material of the wire is

In materials like aluminium and copper, the correct order of magnitude of various elastic moduli is: